350x^2+10x-560=0

Solution for 350x^2+10x-560=0 equation:

350x^2+10x-560=0

a = 350; b = 10; c = -560;
Δ = b2-4ac
Δ = 102-4·350·(-560)
Δ = 784100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{784100}=\sqrt{100*7841}=\sqrt{100}*\sqrt{7841}=10\sqrt{7841}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10\sqrt{7841}}{2*350}=\frac{-10-10\sqrt{7841}}{700}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10\sqrt{7841}}{2*350}=\frac{-10+10\sqrt{7841}}{700}
$